If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x^2-11.5x-2.7=0
a = 1; b = -11.5; c = -2.7;
Δ = b2-4ac
Δ = -11.52-4·1·(-2.7)
Δ = 143.05
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11.5)-\sqrt{143.05}}{2*1}=\frac{11.5-\sqrt{143.05}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11.5)+\sqrt{143.05}}{2*1}=\frac{11.5+\sqrt{143.05}}{2} $
| 6r+10-9r=1+2r | | 84-2x+118-2x+68=360 | | 84°2x+1182x+68=360 | | 84°2x+1182x+68=180 | | -1/3y=28 | | 7k-5=5k-1 | | -6(x+2)+3(1+2x)=9x-12 | | -3(6x+4)=-120 | | -14=3(v-3)-8v | | 5=q/3+3 | | 2x+30=5x-36=180 | | 7x+13=–2 | | 5(x+14)=0 | | j/3+7=3 | | 1/3v-7/3=-1/2 | | 4(2x1)=8x+3 | | 235=59-v | | (19.04)^3x=42 | | 10+2/3x=8 | | 5^(4x)=1250 | | 20–4i=12 | | 10n+2n=12n | | –13u+14u−2u=–8 | | 18j−17j=20 | | 5^(2x-1)=3^(4x) | | 16b−15b=17 | | 0.2k=6 | | 8n=80n= | | 5+(5x2)=15 | | -12-x=-30 | | 5=d/3–4 | | 18+-6m=90 |